If 6 ax + by 3a + 2b 6 bx − ay 3b − 2a then
WebSolve the following simultaneous equations: ax + by = 5 and bx + ay = 3, where a and b are constants. Question Solve the following simultaneous equations: ax+by=5 and bx+ay=3, where a and b are constants. A x= a 2−b 22a−3b,y= b 2−a 23a−5b B x= a 2+b 24a−5b,y= a 2+b 23a−2b C x= b 2−a 25a+2b,y= b 2−a 22a−4b D x= a 2−b 25a−3b,y= a … WebAlso check: Pair Of Linear Equation In Two Variables notes. Definition: When an equation is written in the form of ax+by+c = 0, such equations are called linear equations in two variables. Here, a, b and c are constants (real numbers). Also, the coefficients of x and y i.e., a and b are never equal to zero. Now, if we are given pairs of linear ...
If 6 ax + by 3a + 2b 6 bx − ay 3b − 2a then
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WebCorrect option is B) Given equations are: bx+ay=a 2+b 2 ..... (1) ax−by=0 ..... (2) Now re-arranging both the equation in ax+by+c=0 form: bx+ay−(a 2+b 2)=0 .... (3) ax−by+0=0 ..... (4) From equation (3) and (4) will get a 1=b,b 1=a,c 1=−(a 2+b 2) a 2=a,b 2=−b,c 2=0 Now applying cross multiplication: b 1c 2−b 2c 1x = c 1a 2−c 2a 1y = a 1b 2−a 2b 11 Web6(ax+by)=3a+2b 6(bx-ay)=3b-2a solve the equation ... CLASS 10 - YouTube AboutPressCopyrightContact usCreatorsAdvertiseDevelopersTermsPrivacyPolicy & …
Web29 aug. 2024 · The given equations are 6 (ax + by) = 3a + 2b ⇒6ax + 6by = 3a + 2b ……… (i) and 6 (bx – ay) = 3b – 2a ⇒6bx – 6ay = 3b – 2a ……… (ii) On multiplying (i) by a and (ii) by b, we get Hence, the required … Web23 jun. 2024 · selected Jun 24, 2024 by Hailley The given equations are 6 (ax + by) = 3a + 2b ⇒6ax + 6by = 3a + 2b ……… (i) and 6 (bx – ay) = 3b – 2a ⇒6bx – 6ay = 3b – 2a ……… (ii) On multiplying (i) by a and (ii) by b, we get 6a2x + 6aby = 3a2 + 2ab ………. (iii) 6b2x - 6aby = 3b2 - 2ab ………. (iv) On adding (iii) and (iv), we get 6 (a2 + b2)x = 3 (a2 + b2)
WebCorrect option is D) Rearranging the equations 6ax+6by=3a+2b 6bx−6ay=3b−2a comparing the coefficeint (sonsotants) on LHS and RHS of the equation (1) say it is very clear that … Web8 apr. 2024 · Solve for x and y : 6 (ax+by)= 3a + 2b 6 (bx - ay)= 3b - 2a plzz solve it fast..... See answers Advertisement Advertisement Advertisement New questions in Math 8. If …
WebCorrect option is C) ax+bx−ay−by =(ax+bx)−(ay+by) [Grouping the terms] =(a+b)x−(a+b)y =(a+b)(x−y) [Taking (a + b) common] Was this answer helpful? 0 0 Similar questions Factorise x 3−x 2+ax−a+x−1. Easy View solution > Factorise : a 2+ax+ab+bx Easy View solution > View more More From Chapter Factorisation View chapter > Revise with …
WebYou want to try a split like (x+2)22x+1 = x+2A + (x+2)2Bx Then A+B = 2 and 2A = 1. The decomposition is then (x+2)22x+1 = 21 x+21 + 23(x+2)2x More Items king staples manufacturingWebSolution Verified by Toppr 3bx+3ay=a−6b (i) 3ax−3by=−6a−b (ii) Now multiply equation (i)×a and equation (ii)×b 3abx+3a 2y=a 2−6ba (iii) 3abx−3b 2y=−6ab−b 2 (iv) On substraction (iii) and (iv) , ⇒3y(a 2+b 2)=a 2+b 2 ⇒y= 31 Add y in equation (iii), x=−2 ∴x=−2 and y= 31 Was this answer helpful? 0 0 Similar questions lycee daguin section footWebUntitled - Free download as PDF File (.pdf), Text File (.txt) or read online for free. lycee ctrmWeb22 mei 2024 · Find an answer to your question Solve for x and y 6(ax + by) = 3a + 2b ; 6(bx-ay) = 3b - 2a. Hello there! My name is agenthammerx, a Master Answerer and … lycee darcheWebSolution:Given equations are ax by = a-b and bx-ay = ab.We need to find the values of x and y that satisfy both of these equations.Let's solve the equations one by one:1. ax - by = a - bWe can rewrite this equation as:ax - a = by - ba(x - 1) = b(y - 1)Dividing both sides by (x - 1) and (y - 1), we get:a/b = y - 1 / x - 12. bx - ay = abWe can rewrite this equation as:bx - … kingstanding police training centreWeb15 okt. 2016 · Modified 6 years, 5 months ago. Viewed 1k times. 1. Let T: P3 → P3 be defined by T(ax2 + bx + c) = (3a + b)x2 + (3a − 4b + c)x − a Find the inverse of T. I am … lycee croiset chantillylycee deck guebwiller