Energy needed in breaking a drop of radius

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August undefined, 2024

WebAnswer: one thousand million that is, 10^9 droplets ………………….. a drop of radius R has volume 4/3πR^3 = n*4/3πr^3 you are given n, calculate r from here ... WebNTA Abhyas 2024: Energy needed in breaking a drop of radius R into n identical drops of radii r is given by (A) 4 π T (. n r2 - R2 .) (B) (4/3) π (.

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WebEnergy needed in breaking a drop of radius \( \mathrm{R} \) into \( \mathrm{n} \) drops of radii \( r \) is given bya. \( 4 \pi \mathrm{T}\left(\mathrm{nr}^{... Energy needed in breaking … WebJan 19, 2024 · Energy needed in breaking a drop of radius `R` into `n` drops of radii `r` is given by Energy needed in breaking a drop of radius `R` into `n` drops of radii `r` is given by... brian james race sport for sale

What is the energy required to slip a water drop of radius 1× ... - Quora

http://www.khullakitab.com/physics/pastpapers/grade-11/34/pastpapers WebAug 28, 2024 · Best answer. Initial Radius = R = 10-3 m (= 1 mm) Final Radius = r. Since 1 drop breaks into 1000 small droplets, so. Initial volume = 1000 X Final Volume. commented Sep 18, 2024 by I am the best 234 … WebA number of little droplets of a liquid of surface T density p, all of same redius r, combine to form a single drop of radius R if the total energy released in this process is converted … brian james race transporter 6 used

If t is the surface tension of a fluid then the energy needed to break ...

The energy needed in breaking a drop of radius R into n drops of radius

WebEnergy needed in breaking a drop of radius R into n drops of radii r is given by 4πTnr2−R2 43πr3n−R2 4πTR2−nr2 4πTnr2+R2 Energy needed = Increment in surfa. WebTailbound - A mysterious new convention, a mind-breaking pink mist, powerful monsters, and a shadowy organization pulling the strings. Can you uncover the mystery behind it all, and survive the night?Tailbound is a lewd top-down 2D hack n' slash game, that finishes what my last game, Thirstchasm, set out to do. The game features Zelda-like gameplay, … brian james rear lightsWebEnergy needed in breaking a drop of radius R into n drops each of radius r is given by 4πT (nr 2 - R 2). Explanation: Increase in surface area = n x 4πr 2 - 4πR 2. Required energy … court bailiff uniforms

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Energy needed in breaking a drop of radius

WebApr 15, 2024 · Energy needed in breaking a drop of radius `R` into `n` drops of radii `r` is given by. asked May 27, 2024 in Physics by Navinsingh (86.2k points) class-11; properties-of-matter; 0 votes. 1 answer. The work done is breaking a water drop of radius 1 cm into 64 equal droplets (Surface tension of water is 0.07 N/m) WebThe energy needed to break a drop of radius R into n drops of radii r is given by: 1.4πT(nr2-R2) 2.43π(r3n-R2) 3.4πT(R2-nr2) 4.4πT(r2n+R2) Mechanical Properties of Fluids Physics Practice questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, NCERT Exemplar Questions and PDF …

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WebEnergy needed in breaking a drop of radius R into n drops each of radius r is given by 4πT (nr 2 - R 2). Explanation: Increase in surface area = n x 4πr 2 - 4πR 2. Required energy is equal to the product of surface tension and increase in surface area. = (4πnr 2 - … WebEnergy needed in breaking a drop of radius R into n drops of radii r is given by A. 4πT (nr2 −R2) B. 4 3π(r3n−R2) C. 4πT (R2 −nr2) D. 4πT (nr2+R2) Please scroll down to see …

WebApr 15, 2024 · Energy needed in breaking a drop of radius R R into n n drops of radii r r is given by. A. 4πT (nr2 − R2) 4 π T ( n r 2 - R 2) B. 4 3 π(r3n − R2) 4 3 π ( r 3 n - R 2) C. … WebMar 3, 2024 · The energy break required to break down the radius of the drop, ∴ E = T ( 4 π r 2 n − 4 π R 2) Hence, the correct answer is option (A). Note: Remember that the …

WebA water drop of radius 1 cm is broken into 1000 equal droplets. If the surface tension of water is 0.075 N/m , then the gain in surface enrgy will be WebMay 19, 2024 · 33 4. Note that we have an equation editor built into the site which helps for readability of your post. Apr 30, 2024 at 10:18. Latent heat of vaporisation = 4/3*PR^3 * density * L Change in surface energy = TdA = T*8*PRdR Thus it should not it be, T*8*PRdR= 4/3*P*R^3 * density * L @prathyush poduval Jan 14, 2024 at 5:18. Add a …

WebMay 27, 2024 · A liquid drop of radius R is broken into 1000 drops each of radius r. If T is surface tension, change in surface energy is asked May 31, 2024 in Physics by Navinsingh ( 86.2k points)

WebThe energy required to increase the surface area of the liquid by one unit is defined as surface energy. Energy needed = Increment in surface energy = (surface energy of n … court balancingWebA liquid drop of radius `R` breaks into 64 tiny droplets each of radius `r` if the surface tension of liquid is `T` then gain in energy is court badgeWebStudy with Quizlet and memorize flashcards containing terms like If the pressure inside a star increases slightly, the star will a. implode b. explode c. swell up d. contract, When hydrogen is fused into helium, energy is released from a. gravitational collapse b. conversion of matter to light energy c. the increase in pressure d. the decrease in the … brian james rugby leagueWebThe energy needed to break a drop of radius R into n drops of radii r is given by: 1.4πT(nr2-R2) 2.43π(r3n-R2) 3.4πT(R2-nr2) 4.4πT(r2n+R2) Mechanical Properties of … brian james rs5 widebody race shuttleWebEnergy needed in breaking a drop of radius R into n drops of radii r is given by A B C D Solution The correct option is A Energy needed = Increment in surface energy = … brian james tipping trailersWebEnergy needed in breaking a drop of radius R into n drops of radii r is given by (A) 4 π T ( nr 2- R 2) (B) (4/3) π( r 3 n - R 2) (C) 4 π T ( R 2- Tardigrade Exams brian james tipping trailers reviewsWebA drop of mercury of radius 2 m m is split into 8 identical drops. Find the increase in surface energy. Find the increase in surface energy. Surface tension of mercury = 0.465 J m − 2 brian james sprint shuttle